A) \[{{x}^{2}}-x+1\]
B) \[{{x}^{2}}-x-1\]
C) \[{{x}^{2}}+x-1\]
D) \[{{x}^{2}}+x+1\]
Correct Answer: A
Solution :
Given\[({{m}^{2}}+9){{x}^{2}}+13x+6m\]and\['x'\]. \[1441\times x=5040\times 12\]The required quadratic polynomial is \[\Rightarrow \]. \[x=\frac{5040\times 12}{144}=420\]
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