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10th Class Mathematics Polynomials Question Bank Polynomials

  • question_answer
    The zeros of a quadratic polynomial\[f(x)=2{{x}^{2}}-mx+n\]are\[\alpha \]and\[\beta \]such that\[\alpha -\beta =3\]. Find the value of 'k'.

    A)  10                         

    B)         2

    C)  5                            

    D)         15

    Correct Answer: A

    Solution :

     If a and P are the zeros of the polynomial\[\therefore \] \[=\left( \frac{144}{48}+\frac{384}{48}+\frac{240}{48} \right)=3+8+5=16\]and\[\frac{a}{b}\] Given that\[\frac{c}{d}=\frac{L.C.M.(a,c)}{H.C.F.(b,d)}\], solving\[\Rightarrow \]and\[L.C.M.\], we get\[\frac{6}{14}and\frac{2}{7}\]and\[\Rightarrow \]. \[\frac{L.C.M.(6,2)}{H.C.F.(14,7)}=\frac{6}{7}\]\[\text{7}\times \text{13}+\text{13}=\text{1}0\text{4}=\text{23}\times \text{13}\]and\[\therefore \]                 \[\text{7}\times \text{13}+\text{13}\]


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