A) \[{{x}^{2}}-6x+4\]
B) \[{{a}^{2}}+6a+4\]
C) \[{{p}^{2}}+6p-4\]
D) \[{{m}^{2}}-6m-4\]
Correct Answer: A
Solution :
Given \[p(-1)={{(-1)}^{2}}+3(-1)-2=(-4)\]and \[p(-1)=-4\]are the zeros of a polynomial, \['x'\]and\[1441\times x=5040\times 12\]. \[\Rightarrow \]The required polynomial is \[x=\frac{5040\times 12}{144}=420\] \[219\times =657\]\[3\times =219\] Hence, the polynomial is\[\text{1}0\text{32 }=\text{ 4}0\text{8 }\times \text{ 2 }+\text{ 216}\].
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