A) HF
B) HCl
C) \[HN{{O}_{3}}\]
D) \[{{H}_{2}}S{{O}_{4}}\]
Correct Answer: A
Solution :
We know that greater the difference in electronegativity of two atoms forming a covalent bond. More is its polar nature. In HF there is a much difference in the electronegatives of hydrogen and flourine. Therefore (HF) is a polar compound.
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