A) \[S{{F}_{4}}\]is polar and non-reactive
B) \[S{{F}_{6}}\]is non-polar and very reactive
C) \[S{{F}_{6}}\]is a strong fluorinating agent
D) \[S{{F}_{4}}\]is prepared by fluorinating \[SC{{l}_{2}}\]with \[NaF\]
Correct Answer: B
Solution :
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