A) 7
B) 6
C) 0
D) 9
Correct Answer: D
Solution :
373 a is divisible by 9. \[\Rightarrow 3+7+3+a=13+a\] should be divisible by 9. \[\Rightarrow a=5\] \[473b\] is divisible by 11. \[\Rightarrow 4+3-7-b=0\] or \[11\Rightarrow b=0\] or 11 \[\therefore b=0\] 371 c is divisible by 6. \[\Rightarrow 371c\] is divisible by both 2 and 3. \[\Rightarrow c\]is an even number and 3 + 7 + 1 + c is divisible by 3. \[\Rightarrow c=\text{ }0,\text{ }2,\text{ }4,\text{ }6,\text{ }8\] and 11 + c is divisible by 3. \[\Rightarrow c=4\] \[\therefore a+b+c=5+0+4=9\]
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