A) \[\text{n}\in \text{N}\]
B) Odd values of n
C) Even values of n
D) n is the multiple of 11
Correct Answer: C
Solution :
\[({{10}^{n}}-1)\] is divisible by 11 for even values of n as \[{{10}^{2}}-1=99\], \[{{10}^{4}}-1=9999\], \[{{10}^{6}}-1=999999\] etc., are divisible fay 11.
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