A) \[\frac{\pi }{2}\]
B) \[\pi \]
C) \[2\pi \]
D) None of these
Correct Answer: B
Solution :
Since \[\sin \theta \cos \theta =\frac{1}{2}\sin 2\theta \]. Hence period = \[\frac{2\pi }{2}=\pi \].
You need to login to perform this action.
You will be redirected in
3 sec
