If its perimeter is 108 cm, find the breadth of each rectangle.
A) 10 cm
B) 15 cm
C) 7 cm
D) 28 cm
Correct Answer: C
Solution :
From the figure, clearly the length of each identical rectangle \[=\text{ 2}0\text{ cm }\div \text{ 2 }=\text{ 1}0\text{ cm}\] Perimeter of the given figure = 8 lengths + 4 breadths \[=\text{8}\times \text{1}0+\text{4}\times \text{breadth}=\text{1}0\text{8 cm}\] \[\therefore \] \[\text{4 }\times \text{breadth}=\text{ (1}0\text{8}-\text{8}0\text{) cm }=\text{28 cm}\] \[\therefore \]Breadth \[=\text{ 28 cm }\div \text{ 4}=\text{7 cm}\]
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