| (P) Length of ribbon required to cover the semicircular disc of radius 10 cm is\[51.4\text{ }cm\]. |
| (Q) Ratio of circumference of a circle to its radius is always \[2\pi :1\]. |
| (R) \[500\text{ }{{m}^{2}}=5\]hectares |
| (S) If \[1\text{ }{{m}^{2}}=x\text{ }m{{m}^{2}},\] then the value of x is 100000. |
A)
(P) (Q) (R) (S) T F F F
B)
(P) (Q) (R) (S) F F T F
C)
(P) (Q) (R) (S) T F F T
D)
(P) (Q) (R) (S) T T F F
Correct Answer: D
Solution :
(P) We have, Radius of disc = 10 cm \[\therefore \] Length of ribbon required \[=\left( \frac{1}{2}\times 2\pi r+2r \right)\] \[=\frac{22}{7}\times 10+2\times 10=51.42\,cm\] (Q) \[\frac{Circumference\text{ }of\text{ }circle}{Radius\text{ }of\text{ }circle~~~~~~~}=\frac{2\pi r}{r}=\frac{2\pi }{1}\] (R) 1 hectare \[=10000\,{{m}^{2}}\] \[\therefore \] \[1\,{{m}^{2}}=\frac{1}{10000}\] hectare \[\Rightarrow \] \[500{{m}^{2}}=\frac{500}{10000}\]hectare \[=\frac{1}{20}\] hectare (S) \[1\,{{m}^{2}}=(1000\times 1000)\,m{{m}^{2}}=\times \,m{{m}^{2}}\] \[\therefore \] \[x=1000000\]
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