A) \[375\,c{{m}^{2}}\]
B) \[370\,c{{m}^{2}}\]
C) \[475\,c{{m}^{2}}\]
D) \[450\,c{{m}^{2}}\]
Correct Answer: A
Solution :
Area of rectangle \[ABCD=AB\times BC\] \[=30\times 25\] Now, \[DS=\frac{AD}{2}=\frac{25}{2}=12.5\,cm\] \[DR=\frac{DC}{2}=\frac{30}{2}=15\,cm\] \[\therefore \] Area of \[\Delta DSR\] Area of \[\Delta RCQ\] Area of \[\Delta QBP\]= Area of \[\Delta PAS=\frac{1}{2}\times DS\times DR\] \[=\frac{1}{2}\times 12.5\times 15=93.75\,c{{m}^{2}}\] So, area of shaded region \[=750-4\times 93.75=375\text{ }c{{m}^{2}}\]
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