A) \[5\,\,cm\]
B) \[6\,\,cm\]
C) \[7\,\,cm\]
D) \[8\,\,cm\]
Correct Answer: A
Solution :
We have, area \[=156\text{ }c{{m}^{2}}\] \[\Rightarrow \] \[b\times h=156\] \[AB\times DL=156\] \[DL=\frac{156}{AB}=\frac{156}{13}=12\,cm\] In right \[\Delta \,\,ADL,\] \[A{{D}^{2}}=D{{L}^{2}}+L{{A}^{2}}\] \[A{{L}^{2}}=A{{D}^{2}}-D{{L}^{2}}={{13}^{2}}-{{12}^{2}}=25\] \[\therefore \] \[AL=\sqrt{25}=5\,cm\]You need to login to perform this action.
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