A) 1
B) 2
C) 3
D) 4
Correct Answer: B
Solution :
It is given that, \[kx-3y+6=0\]and \[4x-6y+15=0\]are two parallel lines, i.e., The given lines has no solution or \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{{{b}_{1}}}{{{b}_{2}}}\ne \frac{{{c}_{1}}}{{{c}_{2}}}\] \[\Rightarrow \] \[\frac{k}{4}=\frac{-3}{-6}\ne \frac{6}{15}\] \[\Rightarrow \] \[\frac{k}{4}=\frac{3}{6}\] \[\Rightarrow \] \[k=2\]
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