A) Oxidation of \[C{{u}^{+2}}\]
B) Reduction of \[C{{u}^{+2}}\]
C) Hydrolysis of \[CuS{{O}_{4}}\]
D) Ionization of \[CuS{{O}_{4}}\]
Correct Answer: B
Solution :
\[\overset{\,\,\,0}{\mathop{Zn}}\,+\overset{+2\,\,\,\,\,\,\,\,\,}{\mathop{CuS{{O}_{4}}}}\,\to ZnS{{O}_{4}}+\overset{\,\,\,0}{\mathop{Cu}}\,\] In this reaction \[C{{u}^{2+}}\]change in \[C{{u}^{o}}\], hence it is called as reduction reaction.
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