A) \[VO_{2}^{+}\,\to \,{{V}_{2}}{{O}_{3}}\]
B) \[Na\,\to \,N{{a}^{+}}\]
C) \[CrO_{4}^{2-}\,\to \,C{{r}_{2}}O_{7}^{2-}\]
D) \[Z{{n}^{2+}}\,\to \,Zn\]
Correct Answer: C
Solution :
\[\overset{*\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{CrO_{4}^{2-}}}\,\] \[\overset{*\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{C{{r}_{2}}O_{7}^{2-}}}\,\] \[x+[(-2)\times 4]=-2\] \[2x+(-2)\times 7=-2\] \[x=8-2=+6\] \[2x=14-2=12\], \[x=\frac{12}{2}=+6\] In this reaction oxidation and reduction are not involved because there is no change in oxidation number.
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