A) \[2N{{O}_{2}}\,\to \,\,{{N}_{2}}{{O}_{4}}\]
B) \[2N{{O}_{2}}+{{H}_{2}}O\,\to \,HN{{O}_{2}}+HN{{O}_{3}}\]
C) \[N{{H}_{4}}OH\,\to \,NH_{4}^{+}+O{{H}^{-}}\]
D) \[CaC{{O}_{3}}\,\to \,CaO+C{{O}_{2}}\]
Correct Answer: B
Solution :
\[\overset{+4}{\mathop{2N{{O}_{2}}}}\,+{{H}_{2}}O\to HN{{O}_{2}}+\overset{+5}{\mathop{HN{{O}_{3}}}}\,\]. In this reaction oxidation state changes.
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