A) \[CO\]
B) \[C{{H}_{4}}\]
C) \[C{{H}_{2}}C{{l}_{2}}\]
D) \[C{{H}_{3}}Cl\]
Correct Answer: C
Solution :
\[x+2\times (+1)+2(-1)=0\] \[x+2-2=0\]; \[x=0\,\,in\,\,C{{H}_{2}}C{{l}_{2}}\].
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