A) 0 to 2
B) 2 to 0
C) - 2 to 0
D) - 2 to - 1
Correct Answer: C
Solution :
Oxidation state of sulphur in \[{{H}_{2}}S\] is '2, while it is zero in 'S' i.e. in this reaction oxidation of sulphur and reduction of chlorine is takes place.
You need to login to perform this action.
You will be redirected in
3 sec
