JEE Main & Advanced Chemistry Redox Reactions / रेडॉक्स अभिक्रियाएँ Question Bank Oxidation number and Oxidation state

  • question_answer
    The oxidation number of iron in the compound \[{{K}_{4}}[Fe{{(CN)}_{6}}]\] is [NCERT 1976; MNR 1986; AIIMS 2000]

    A)                 + 6         

    B)                 + 4

    C)                 + 3         

    D)                 + 2

    Correct Answer: D

    Solution :

           \[\overset{\,\,\,*\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{{{K}_{4}}[Fe{{(CN)}_{6}}]}}\,\]            \[1\times 4+x+(-1\times 6)=0,\] \[4+x-6=0\]            \[x=+\,2\].                                 In this complex compound Iron show + 2 oxidation state.


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