A) \[[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{2}}\]
B) \[[Fe{{({{H}_{2}}O)}_{6}}S{{O}_{4}}]\]
C) \[[Ni{{(CO)}_{4}}]\]
D) \[[Fe{{({{H}_{2}}O)}_{3}}]{{(OH)}_{2}}\]
Correct Answer: C
Solution :
Nickle shows zero oxidation state in carbonyl complex.
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