A) +4
B) +6
C) +2
D) +3
Correct Answer: D
Solution :
\[{{K}_{2}}C{{r}_{2}}{{O}_{7}}+6KI+7{{H}_{2}}S{{O}_{4}}\to 4{{K}_{2}}S{{O}_{4}}+C{{r}_{2}}{{(S{{O}_{4}})}_{3}}\] \[+7{{H}_{2}}O+3{{I}_{2}}\] \[\overset{*}{\mathop{C}}\,{{r}_{2}}{{(S{{O}_{4}})}_{3}}\to 2\overset{+3}{\mathop{Cr}}\,+3SO_{4}^{2-}\]
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