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JEE Main & Advanced Chemistry Redox Reactions / रेडॉक्स अभिक्रियाएँ Question Bank Oxidation number and Oxidation state

  • question_answer
    Oxidation number of nitrogen in \[NaN{{O}_{2}}\] is [Pb. CET 2000]

    A) + 2         

    B) + 3

    C) + 4         

    D) - 3

    Correct Answer: B

    Solution :

    Let the oxidation number of \[N\] in \[NaN{{O}_{2}}\] be \[x\]                    \[+1+x+(-2)\times 2=0\]                                 \[1+x-4=0\];  \[x=+3\]


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