question_answer

When a 2.0 kg body is suspended by a spring, the spring is stretched. If the body is pulled down slightly and released, it oscillates up and down. What force is applied on the body by the spring when it passes through the mean position? (\[g\text{ }=\mathbf{9}.\mathbf{8}\]newton/kg).

Answer:

                There is no acceleration in the body at the mean position, hence the resultant force applied by the spring will be exactly equal to the weight of the body i.e., \[2\times 9.8\] or \[\text{19}.\text{6}\] newton.