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JEE Main & Advanced Physics Wave Mechanics Question Bank Organ Pipe (Vibration of Air Column)

  • question_answer
    If the length of a closed organ pipe is 1.5 m and velocity of sound is 330 m/s, then the frequency for the second note is                 [CBSE PMT 2002]

    A)            220 Hz                                     

    B)            165 Hz

    C)            110 Hz                                     

    D)            55 Hz

    Correct Answer: B

    Solution :

               For closed pipe second note = \[\frac{3v}{4l}=\frac{3\times 330}{4\times 1.5}=165\]\[Hz\].


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