A) \[{{K}_{2}}O.A{{l}_{2}}{{O}_{3}}.6Si{{O}_{2}}\]
B) \[{{K}_{2}}{{O}_{3}}.A{{l}_{2}}{{O}_{3}}.6S{{i}_{2}}.{{O}_{2}}.2{{H}_{2}}O\]
C) \[A{{l}_{2}}{{O}_{3}}.2Si{{O}_{2}}.2{{H}_{2}}O\]
D) \[3MgO.4Si{{O}_{2}}.{{H}_{2}}O\]
Correct Answer: A
Solution :
Felspar is \[{{K}_{2}}O.A{{l}_{2}}{{O}_{3}}.6Si{{O}_{2}}\]
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