question_answer

The smallest number which when divided by 4, 6, 10, 15 gives the same remainder 3 is

A)  57                                         

B)  123

C)  63                         

D)              39

Correct Answer: C

Solution :

    \[\therefore \] LCM of 4, 6, 10, \[15=2\times 5\times 3\times 2\times 1\times 1\times 1=60\] \[\therefore \] Required number = 60 + 3 = 63.