A) \[\frac{7}{12}\]
B) \[\frac{35}{96}\]
C) \[\frac{-5}{96}\]
D) \[\frac{77}{96}\]
Correct Answer: B
Solution :
(b): Let 'x' be subtrahend \[\therefore \left( \frac{3}{4}-\frac{6}{16}+\frac{5}{24} \right)-x=7/32\] \[\Rightarrow \frac{3}{4}-\frac{6}{16}+\frac{5}{24}-7/32=x\] \[\Rightarrow \frac{72-36+20-21}{96}=x\] \[\Rightarrow \frac{35}{96}=x\].You need to login to perform this action.
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