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JEE Main & Advanced Chemistry Coordination Chemistry Question Bank Nomenclature, Oxidation state and EAN number

  • question_answer
    In \[{{K}_{4}}\left[ Fe{{\left( CN \right)}_{6}} \right],\] the E.A.N. of \[Fe\] is [DCE 2000]

    A) 33

    B) 35

    C) 36

    D) 26

    Correct Answer: C

    Solution :

    EAN =Atomic number - Oxidation state + 2 × number of Ligands =  26 - 2 + 2 (6) = 36.


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