A) \[1{{s}^{2}},\] \[2{{s}^{2}}2{{p}^{6}},\] \[3{{s}^{2}}\]
B) \[1{{s}^{2}},\] \[2{{s}^{2}}2{{p}^{6}},\] \[3{{s}^{1}}\]
C) \[1{{s}^{2}},\] \[2{{s}^{2}}2{{p}^{6}}\]
D) \[1{{s}^{2}},\] \[2{{s}^{2}}2{{p}^{6}},\] \[3{{s}^{2}}3{{p}^{6}},\] \[4{{s}^{2}}\]
Correct Answer: C
Solution :
\[1{{s}^{2}}\,2{{s}^{2}}\,2{{p}^{6}}\,\to \,\text{Neon}\]
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