A) \[PC{{l}_{3}}\]
B) \[BiC{{l}_{3}}\]
C) \[SbC{{l}_{3}}\]
D) \[CC{{l}_{4}}\]
Correct Answer: A
Solution :
Because phosphorous is most electronegative element out of \[{{H}_{2}}S{{O}_{4}}+2HI\,\to \ 2{{H}_{2}}O+\underset{\text{Violet vapour}}{\mathop{{{I}_{2}}+S{{O}_{2}}\uparrow }}\,\] and C.
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