A) Sodium hydride
B) Sodium amide
C) Sodium atoms
D) Solvated electrons
Correct Answer: D
Solution :
Sodium metal in liq. \[N{{H}_{3}}\] solution shows strong reducing power due to solvated electron. \[Na+(x+y)N{{H}_{3}}\] ⇌ \[{{[Na{{(N{{H}_{3}})}_{x}}]}^{+}}+\underset{\text{solvated}\,\text{electron}}{\mathop{{{[e{{(N{{H}_{3}})}_{y}}]}^{-}}}}\,\]
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