A) \[N{{H}_{4}}Cl\]
B) \[N{{H}_{4}}N{{O}_{3}}\]
C) \[{{(N{{H}_{4}})}_{2}}C{{O}_{3}}\]
D) \[N{{H}_{4}}OH\]
Correct Answer: A
Solution :
\[N{{H}_{4}}Cl+NaN{{O}_{2}}\xrightarrow{\Delta }N{{H}_{4}}N{{O}_{2}}\] \[N{{H}_{4}}N{{O}_{2}}\xrightarrow{{}}{{N}_{2}}+2{{H}_{2}}O\]
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