A) \[N{{H}_{3}}\]
B) \[{{N}_{2}}{{H}_{4}}\]
C) \[{{N}_{2}}{{H}_{2}}\]
D) \[{{N}_{3}}H\]
Correct Answer: D
Solution :
\[\underset{\text{Hydrazoic acid}}{\mathop{{{N}_{3}}H}}\,\]⇌ \[N_{3}^{-}+{{H}^{+}}\]
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