A) \[HN{{O}_{3}}\]
B) \[{{H}_{2}}S{{O}_{4}}\]
C) \[HCl\]
D) \[HN{{O}_{2}}\]
Correct Answer: D
Solution :
\[HN{{O}_{2}}\] can be either reduced to nitric oxide \[(NO)\] or oxidised to nitric acid and hence it acts both as an oxidising as well as a reducing agent. \[2HN{{O}_{2}}\,\to \,2NO+{{H}_{2}}O+[O]\] \[HN{{O}_{2}}+[O]\,\to \,HN{{O}_{3}}\]
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