A) \[N{{H}_{4}}Cl\]
B) \[{{(N{{H}_{4}})}_{2}}S{{O}_{4}}\]
C) \[N{{H}_{4}}Cl+NaN{{O}_{3}}\]
D) \[N{{H}_{4}}N{{O}_{3}}\]
Correct Answer: D
Solution :
\[C{{a}_{3}}{{P}_{2}}+3{{H}_{2}}O\,\to \,3Ca{{(OH)}_{2}}+2P{{H}_{3}}\]
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