A) \[0.2\times {{10}^{-2}}\mu \ W/{{m}^{2}}\]
B) \[1\times {{10}^{-2}}\mu \ W/{{m}^{2}}\]
C) \[4\times {{10}^{-4}}\mu \ W/{{m}^{2}}\]
D) \[5\times {{10}^{-2}}\mu \ W/{{m}^{2}}\]
Correct Answer: C
Solution :
\[I\propto \frac{1}{{{r}^{2}}}\Rightarrow \frac{{{I}_{2}}}{{{I}_{1}}}=\frac{r_{1}^{2}}{r_{2}^{2}}\]Þ \[\frac{{{I}_{2}}}{1\times {{10}^{-2}}}=\frac{{{2}^{2}}}{{{10}^{2}}}=\frac{4}{100}\] Þ \[{{I}_{2}}=\frac{4\times {{10}^{-2}}}{100}\] = \[4\times {{10}^{-4}}\ \mu \ W/{{m}^{2}}\]
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