JEE Main & Advanced Mathematics Permutations and Combinations Question Bank Multinomial Theorem, Number of Divisors, Miscellaneous problems

  • question_answer
    Number of divisors of \[n=38808\] (except 1 and n) is [RPET 2000]

    A) 70

    B) 68

    C) 72

    D) 74

    Correct Answer: A

    Solution :

    Since, 38808 = 8 × 4851 \[=8\times 9\times 539=8\times 9\times 7\times 7\times 11={{2}^{3}}\times {{3}^{2}}\times {{7}^{2}}\times 11\] So, number of divisors = (3 + 1) (2 + 1) (2 + 1) (1 + 1) = 72. This includes two divisors 1 and 38808. Hence, the required number of divisors = 72 - 2 = 70.


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