A) \[\frac{3{{u}^{2}}}{g}\]
B) \[\frac{4{{u}^{2}}}{g}\]
C) \[\frac{6{{u}^{2}}}{g}\]
D) \[\frac{9{{u}^{2}}}{g}\]
Correct Answer: B
Solution :
Let \[h\] be the height of the tower We know, \[{{v}^{2}}={{u}^{2}}+2as\] \[\therefore \] \[{{(-3u)}^{2}}={{u}^{2}}+2(-g)(-h)\] \[\Rightarrow \] \[9{{u}^{2}}={{u}^{2}}+2gh\] \[\Rightarrow \] \[8{{u}^{2}}=2gh\] \[\Rightarrow \] \[h=\frac{4{{u}^{2}}}{g}\]
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