question_answer

A stone is thrown horizontally with a speed \[\sqrt{2gh}\] from the top of a wall of height h. It strikes the level ground through the foot of the wall at a distance \[x\] from the wall. What is the value of \[x\]?

Answer:

                As \[h=\frac{1}{2}g{{t}^{2}}\]                 \[\therefore \]  \[t=\sqrt{\frac{2h}{g}}\] \[\text{Speed =}\frac{\text{Distance}}{\text{Time}}\] \[\sqrt{2gh}=\frac{x}{\sqrt{2h/g}}\]                 or            \[x=\sqrt{2gh}\times \sqrt{\frac{2h}{g}}=\mathbf{2h}\]