A) 273 K
B) 606 K
C) 303 K
D) 403 K
Correct Answer: B
Solution :
\[\frac{{{U}_{S{{O}_{2}}}}}{{{U}_{{{O}_{2}}}}}=\sqrt{\frac{{{M}_{{{O}_{2}}}}{{T}_{S{{O}_{2}}}}}{{{M}_{S{{O}_{2}}}}{{T}_{{{O}_{2}}}}}}=\sqrt{\frac{32\times }{64\times }\frac{{{T}_{S{{O}_{2}}}}}{303}}=1\] \[1=\frac{32\times }{64}\frac{{{T}_{S{{O}_{2}}}}}{303}\] Þ \[{{T}_{S{{O}_{2}}}}=606\]
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