A) \[{{m}^{1/2}}\]
B) \[{{m}^{0}}\]
C) \[{{m}^{-1/2}}\]
D) m
Correct Answer: C
Solution :
\[{{V}_{rms}}=\sqrt{\frac{3KT}{Molecular\,weight}}\] i.e. \[{{V}_{rms}}\propto \frac{1}{\sqrt{m}}\propto {{(m)}^{-\frac{1}{2}}}\]
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