A) 7, 6, 8
B) 1, 0, 2
C) 6, 6, 6
D) 8, 6, 8
Correct Answer: A
Solution :
Molecular orbital electronic configuration of these species are : \[O_{2}^{-}(17{{e}^{-}})=\]\[\sigma 1{{s}^{2}}{{\sigma }^{*}}1{{s}^{2}},\sigma 2{{s}^{2}}{{\sigma }^{*}}2{{s}^{2}},\sigma 2{{p}_{x}}^{2},\pi 2{{p}_{y}}^{2},\]\[\pi 2{{p}_{z}}^{2},{{\pi }^{*}}2{{p}_{y}}^{2}{{\pi }^{*}}2{{p}_{z}}^{1}\] \[{{O}_{2}}(16e)=\]\[\sigma 1{{s}^{2}}{{\sigma }^{*}}1{{s}^{2}},\sigma 2{{s}^{2}}{{\sigma }^{*}}2{{s}^{2}},\sigma 2{{p}_{x}}^{2},\pi 2{{p}_{y}}^{2},\]\[\pi 2{{p}_{z}}^{2}{{\pi }^{*}}2{{p}_{y}}^{1}{{\pi }^{*}}2{{p}_{z}}^{1}\] \[O_{2}^{2-}(18e)=\] \[\sigma 1{{s}^{2}}{{\sigma }^{*}}1{{s}^{2}},\sigma 2{{s}^{2}}{{\sigma }^{*}}2{{s}^{2}},\sigma 2{{p}_{x}}^{2},\pi 2{{p}_{y}}^{2},\]\[\pi 2{{p}_{z}}^{2}{{\pi }^{*}}2{{p}_{y}}^{2}{{\pi }^{*}}2{{p}_{z}}^{2}\] Hence number of antibonding electrons are 7,6,and 8 respectively.
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