JEE Main & Advanced Chemistry Chemical Bonding and Molecular Structure / रासायनिक आबंधन एवं आणविक संरचना Question Bank Molecular orbital theory

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    The paramagnetic property of the oxygen molecule due to the presence of unpaired electorns present in [Kerala PMT 2004]

    A)                 \[{{(\sigma 2{{p}_{x}})}^{1}}\] and \[{{({{\sigma }^{*}}2{{p}_{x}})}^{1}}\]

    B)                  \[{{(\sigma 2{{p}_{x}})}^{1}}\]and \[{{(\pi 2{{p}_{y}})}^{1}}\]

    C)                 \[{{(\pi *2{{p}_{y}})}^{1}}\] and \[{{(\pi *2{{p}_{z}})}^{1}}\]

    D)                 \[{{(\pi *2{{p}_{y}})}^{1}}\]and \[{{(\pi 2{{p}_{y}})}^{1}}\]

    E)                 \[{{(\pi *2{{p}_{z}})}^{1}}\] and \[{{(\pi 2{{p}_{z}})}^{1}}\]

    Correct Answer: C

    Solution :

     The paramagnetic property in oxygen came through unpaired electron which can be explained by molecular orbital theory.                    So 2 unpaired of electron present in \[\pi \ 2p_{y}^{*}\ \text{and}\ \pi \ 2p_{z}^{*}\].


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