A) \[{{N}_{2}},O_{2}^{2+}\]
B) \[{{N}_{2}}\], \[O_{2}^{-}\]
C) \[N_{2}^{-}\], \[{{O}_{2}}\]
D) \[O_{2}^{+}\], \[{{N}_{2}}\]
Correct Answer: A
Solution :
B.O.\[=\frac{1}{2}[\,{{N}_{b}}-{{N}_{a}}]\] \[{{N}_{2}}=\frac{1}{2}[10-4]=\frac{6}{2}=3\]; \[O_{2}^{2+}=\frac{1}{2}[10-4]=\frac{6}{2}=3.\]
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