JEE Main & Advanced Chemistry Chemical Bonding and Molecular Structure / रासायनिक आबंधन एवं आणविक संरचना Question Bank Molecular orbital theory

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    An atom of an element A has three electrons in its outermost shell and that of B has six electrons in the outermost shell. The formula of the compound between these two will be            [CPMT 1974, 84; RPMT 1999]

    A)                 \[{{A}_{3}}{{B}_{4}}\]    

    B)                 \[{{A}_{2}}{{B}_{3}}\]

    C)                 \[{{A}_{3}}{{B}_{2}}\]    

    D)                 \[{{A}_{2}}{{B}_{3}}\]

    Correct Answer: B

    Solution :

                    Valency of A is 3 while that of B is 2 so according to Criss Cross rule the formula of the compound between these two will be \[{{A}_{2}}{{B}_{3}}\].


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