A) \[\frac{5}{41}\]
B) \[\frac{4}{41}\]
C) \[\frac{5}{39}\]
D) None of these
Correct Answer: C
Solution :
Product of the fractions \[=\frac{4}{13}\times \frac{5}{12}\,=\frac{4\times 5}{13\times 12}\,=\frac{20}{156}\] The HCF of numerator and denominator = 4, therefore, the lowest or reduced term of the resulting product = \[\frac{20\div 4}{156\div 4}=\frac{4}{39}\]
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