A) ac
B) bd
C) \[(b-a)(d-c)\]
D) None of these
Correct Answer: B
Solution :
\[{{\Delta }_{2}}{{\Delta }_{1}}=\left| \begin{matrix} 1 & 0 \\ c & d \\ \end{matrix} \right|\,\,\left| \,\begin{matrix} 1 & 0 \\ a & b \\ \end{matrix}\, \right|=\left| \,\begin{matrix} 1 & 0 \\ c+ad & bd \\ \end{matrix}\, \right|=bd\].You need to login to perform this action.
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