A) 2 kW
B) 1/2 kW
C) 4 kW
D) 8 Kw
Correct Answer: C
Solution :
\[P\propto {{N}^{2}},\] \[{{P}_{2}}={{P}_{1}}{{\left( \frac{{{N}_{2}}}{{{N}_{1}}} \right)}^{2}}=1\times {{\left( \frac{400}{200} \right)}^{2}}=4kW\]
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