| Length of rectangle (cm) | Breadth of rectangle (cm) | Area \[\text{(c}{{\text{m}}^{\text{2}}}\text{)}\] | Perimeter (cm) |
| 25 | P | 300 | Q |
| 18 | R | S | 66 |
A)
P Q R S 12 74 15 207
B)
P Q R S 12 15 74 270
C)
P Q R S 12 74 15 270
D)
P Q R S 42 15 270 74
Correct Answer: C
Solution :
\[\text{Area = 300 c}{{\text{m}}^{\text{2}}}\] \[\Rightarrow \text{ }25\times p=300\Rightarrow P=12\text{ }cm\] \[\therefore \] Perimeter\[=2(12+25)=74\text{ }cm\] So, \[\text{P=12, Q=74}\] Also, Perimeter = 66 \[\Rightarrow 2(18+R)=66\Rightarrow 18+R=33\] \[\Rightarrow \text{R}=15\text{ cm}\] and Area \[=S=15\times 18=270\text{ }c{{m}^{2}}\] \[\therefore \] R = 15 and S = 270
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