A) 1580 \[c{{m}^{2}}\]
B) 2310 \[c{{m}^{3}}\]
C) 3210 \[c{{m}^{3}}\]
D) 1576 \[c{{m}^{2}}\]
Correct Answer: B
Solution :
(b): VOL. \[=area\text{ }of\text{ }base\times height\] \[=154\times 15\] = 2310
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